Alternating CurrentHard
Question
A coil has an inductance of 
H and is joined in series with a resistance of 220 Ω. When an alternating e.m.f. of 220 V at 50 c.p.s. is applied to it, then the watt less component of the rms current in the circuit is
H and is joined in series with a resistance of 220 Ω. When an alternating e.m.f. of 220 V at 50 c.p.s. is applied to it, then the watt less component of the rms current in the circuit isOptions
A.5 ampere
B.0.5 ampere
C.0.7 ampere
D.7 ampere
Solution
Watt less current = Irms sin φ
Where tan φ =
= 1
and Irms =
Where tan φ =
= 1and Irms =
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