Definite IntegrationHard
Question
The area of the region enclosed between the curves 7x2 + 9y + 9 = 0 and 5 x2 + 9 y + 27 = 0 is:
Options
A.2
B.4
C.8
D.16
Solution
7x2 + 9y + 9 = 0
y1 = - 7/9 x2 - 1
y2 = - 5/9 x2 - 3
from -
x2 - 1 = - 
x2 - 3 ⇒ x = ± 3
Area =
⇒ Area = 8
y1 = - 7/9 x2 - 1
y2 = - 5/9 x2 - 3
from -
x2 - 1 = - x2 - 3 ⇒ x = ± 3Area =
⇒ Area = 8Create a free account to view solution
View Solution FreeMore Definite Integration Questions
The value of sin−1 √t dt + cos−1 √t dt is-...The value of dx is...dx equals-...The ratio in which the curve y = x2 divides the region bounded by the curve; y = sin and the x-axis as x varies from 0 t...The area of the region bounded in first quadrant by y = x1/3; y = - x2 + 2x + 3; y = 2x - 1 and the axis of ordinates is...