Application of DerivativeHard
Question
If P is a point on the curve 5x2 + 3xy + y2 = 2 and O is the origin, then OP has
Options
A.minimum value 
B.minimum value 
C.maximum value
D.maximum value 2
Solution
x = r cos θ, y = r sin θ
⇒
= 5 (1 + cos 2θ) + 3 sin 2θ + 1 - cos 2θ
= 6 + 4 cos 2θ + 3 sin 2θ, which has maximum 11 and minimum 1
∴ OP has minimum
and maximum 2.
⇒
= 6 + 4 cos 2θ + 3 sin 2θ, which has maximum 11 and minimum 1
∴ OP has minimum
Create a free account to view solution
View Solution FreeMore Application of Derivative Questions
Equation of the line through the point (1/2, 2) and tangent to the parabola y = + 2 and secant to the curve y = is -...The number of values of x, where the function f (x) = cos x + cos (√2x) attains its maximum, is...Let f(x) = (x − 4) (x − 5) (x − 6) (x − 7) then...The abscissa of the point on the curve ay2 = x3, the normal at which cuts off equal intercepts from the axes is-...The sum of the intercepts made by a tangent to the curve √x + √y = 4 at point (4, 4) on coordinate axes is-...