Application of DerivativeHard
Question
The curve y - exy + x = 0 has a vertical tangent at
Options
A.(1, 1)
B.(0, 1)
C.(1, 0)
D.no point
Solution
y - exy + x = 0
Differentiating w.r.t. to y
1 - exy
= 0
= 0
1 - xexy = 0
xexy = 1 ⇒ x = 1 , y = 0
∴ Point is (1, 0)
Differentiating w.r.t. to y
1 - exy
1 - xexy = 0
xexy = 1 ⇒ x = 1 , y = 0
∴ Point is (1, 0)
Create a free account to view solution
View Solution FreeMore Application of Derivative Questions
For the curve x = t2 + 3t - 8, y = 2t2 - 2t - 5, at point (2, - 1)...The equation of tangent to the curve √x + √y = √a at the point (x1, y1) is-...A point is moving along the curve y3 = 27x. The interval in which the abscissa changes at slower rate than ordinate, is ...The sum of the intercepts made by a tangent to the curve √x + √y = 4 at point (4, 4) on coordinate axes is-...The slope of the tangents to the curve y = (x + 1) (x- 3) at the points where it crosses x- axis are-...