Application of DerivativeHard
Question
If tangent to curve 2y3 = ax2 + x3 at point (a, a) cuts off intercepts a, b on co-ordinate axes, where
α2 + β2 = 61, then the value of ′a′ is equal to
α2 + β2 = 61, then the value of ′a′ is equal to
Options
A.20
B.25
C.30
D.-30
Solution
2y3 = ax2 + x3
6y2
= 2ax + 3x2
Tangent at (a, a) is 5x - 6y = - a
α = -a/5 , β = a/6
α2 + β2 = 61 ⇒
= 61
a2 = 25.36
a = ± 30
6y2
= 2ax + 3x2Tangent at (a, a) is 5x - 6y = - a
α = -a/5 , β = a/6
α2 + β2 = 61 ⇒
= 61a2 = 25.36
a = ± 30
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