Set, Relation and FunctionEasy
Question
A function f from the set of natural numbers to integers defined by
f(n) =
is
f(n) =
isOptions
A.one-one but not onto
B.onto but not one-one
C.one-one and onto both
D.neither one-one nor onto
Solution
Clearly both one - one and onto
Because if n is odd, values are set of all non - negative integers and if n is an even, values
are set of all negative integers.
Hence, (C) is the correct answer.
Because if n is odd, values are set of all non - negative integers and if n is an even, values
are set of all negative integers.
Hence, (C) is the correct answer.
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