Height and DistanceEasy
Question
From the top of a 64 metres high tower, a stone is thrown upwards vertically with the velocity of 48 m/s. The greatest height (in metres) attained by the stone, assuming the value of the gravitational acceleration g = 32 m/s2, is :
Options
A.128
B.88
C.112
D.100
Solution
At maximum height v = 0
Now v2 = u2 − 2gh
⇒ 0 = (48)2 − 2(32)h.
⇒ h = 36
Maximum height = 36 + 64 = 100 mt
Now v2 = u2 − 2gh
⇒ 0 = (48)2 − 2(32)h.
⇒ h = 36
Maximum height = 36 + 64 = 100 mt
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