Height and DistanceHard
Question
A tower stands at the centre of a circular park. A and B are two points on the boundary of the park such that AB (= a) subtends an angle of 60o at the foot of the tower, and the angle of elevation of the top of the tower from A or B is 30o. The height of the tower is
Options
A.
B.2a√3
C.
D.a√3
Solution
ᐃOAB is equilateral
∴ OA = OB = AB = a
Now tan 30o =
∴ h =
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