Differential EquationHard
Question
The solution of the differential equation ydx − (x + 2y2)dy = 0 is x = f(y). If f(−1) = 1, then f(1) is equal to :
Options
A.4
B.3
C.1
D.2
Solution
= 2dyd
= 2dyx/y = 2y + c
⇒ c = 1
⇒ x/y = 2y + 1
put y = 1
f(1) = 3
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