Differential EquationEasy
Question
The solution of the differential equation (1 + x2) (1+ y) dy + (1 + x) (1+ y2) dx = 0 is-
Options
A.tan−1 x + log (1 + x2) + tan−1 y + log (1 + y2) = c
B.tan−1 x − 
log (1 + x2) + tan−1 y − 
log (1 + y2) = c
log (1 + x2) + tan−1 y − log (1 + y2) = cC.tan−1 x + log (1 + x2) + tan−1 y + log (1 + y2) = c
log (1 + x2) + tan−1 y + log (1 + y2) = cD.None of these
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