Wave motionHard
Question
In a Young′s double slit experiment with light of wavelength λ the separation of slits is d anddistance of screen is D such that D >> d >> λ. If the fringe width is β, the distance from point ofmaximum intensity to the point where intensity falls to half of maximum intensity on either side is:
Options
A.β/6
B.β/3
C.β/4
D.β/2
Solution
2I0 = 4I0 cos2 
ᐃφ =
ᐃφ =
ᐃx
ᐃx =
....... (i)
= β .........(ii)
Multiply both y =
ᐃφ =
ᐃφ =
ᐃxᐃx =
....... (i) = β .........(ii)Multiply both y =
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