SHMEasy
Question
A cylindrical block of wood (density = 650 kg m-3), of base area 30cm2 and height 54 cm, floats in a liquid of density 900 kg m-3. The block is depressed slightly and then released. The time period of the resulting oscillations of the block would be equal to that of a simple pendulum of length (nearly) :
Options
A.52 cm
B.65 cm
C.39 cm
D.26 cm
Solution
mg = FB
h = Length of block immerged in water
650 × A × 54 × 10-2g = 900 × A × hg
h = 0.39m = 39 cm. Option (3)
Create a free account to view solution
View Solution FreeMore SHM Questions
A child swinging on a swing in sitting position, stands up, then the time period of the swing will...The period of small oscillations of a simple pendulum of length l if its point of suspension O moves a with a constant a...The equation of a simple harmonic wave is given byy = 3 sin (50t - x) where x and y are in metres and t is in seconds. T...The speed v of a particle moving along a straight line, when it is at a distance (x) from a fixed point of the line is g...If a simple pendulum oscillates with an amplitude of 50mm and time period of 2 sec then its maximum velocity is :...