Magnetic field due to currentEasy
Question
A wire carrying current I is tied between points P and Q and is in the shape of a circular arch of radius R due to a uniform magnetic field B (perpendicular to the plane of the paper, shown by xxx) in the vicinity of the wire. If the wire subtends an angle 2θ0 at the centre of the circle (of which it forms an arch) then the tension in the wire is :
Options
A.
B.
C.IBR
D.
Solution
For small arc length 2T sin θ = BIR 2θ
T = BIR
T = BIR
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