JEE AdvancedMagnetic field due to currentHard
Question
A particle of charge + q and mass m moving under the influence of a uniform electric field Eî and uniform magnetic field B
follows a trajectory from P to Q as shown in figure. The velocities at P and Q are vî and -2ĵ. Which of the following statement(s) is/are correct ?
follows a trajectory from P to Q as shown in figure. The velocities at P and Q are vî and -2ĵ. Which of the following statement(s) is/are correct ?Options
A.E = 
B.Rate of work done by the electric field at P is
C.Rate of work done by the electric field at P is zero
D.Rate of work done by both the fields at Q is zero
Solution
Work done by E.F = qE2a = 
m(4v2 - v2)
⇒ E =
Rate of work done by E.F at
P =
= 
Rate of work done by E.F and
M.F at Q : q
= 0
m(4v2 - v2)⇒ E =
Rate of work done by E.F at
P =
= Rate of work done by E.F and
M.F at Q : q
= 0Create a free account to view solution
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