Momentum and CollisionEasy
Question
A block of mass m = 10 kg rests on a horizontal table. The coefficient of friction between the block and thetable is 0.05. When hit by a bullet of mass 50 g moving with speed υ, that gets embedded in it, the blockmoves and come to stop after moving a distance of 2m on the table. If a freely falling object were to acquirespeed υ/10 after being dropped from height H, then neglecting energy losses and taking g = 10 ms-2, the valueof H is close to :
Options
A.0.2 km
B.0.3 km
C.0.5 km
D.0.4 km
Solution
Momentum conservation 0.05V = 10V0
0 - V20 = 2(-μg)2
V0 = √2
object falling from height H.
H = 40 m = 0.04 km
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