Momentum and CollisionHard
Question
Find the center of mass (x,y,z) of the following stricture of four identical of four identical cubes if the length of each side of cube is 1 unit.
Options
A.(1 / 2, 1 / 2, 1 / 2)
B.(1 / 3, 1 / 3, 1 / 3)
C.(3 / 4, 3 / 4, 3 / 4)
D.(1 / 2, 3 / 4, 1 / 2)
Solution
First find the center of mass each cube, It is located by symmetry : (0.5, 0.5, 0.5), (1.5, 0.5, 0.5), (0.5, 1.5, 0.5), (0.5, 0.5, 1.5), Now we find the centre of mass by treating COM of each cube as a point particle :
xCOM =
= 0.75 ; yCOM = 
= 0.75
zCOM =
= 0.75
xCOM =
= 0.75 ; yCOM = = 0.75zCOM =
= 0.75Create a free account to view solution
View Solution FreeMore Momentum and Collision Questions
Two vessels A and B have the same base area and contain water to the same height, but the mass of water in A is four tim...The diagram shows a force-extension graph for a rubber band.Consider the following statementsI. It will be easier to com...A wooden block of volume 1000 cm3 is suspended from a spring balance. Its weight is 12 N in air. It is suspended in wate...The barometric pressure and height on the earth are 105 Pa and 760 mm respectively. If it is taken to moon, then baromet...On a smooth carom board, a coin moving in negative y–direction with a speed of 3 m/s is being hit at the point (4, 6) by...