AIPMT | 2015Heat TransferEasy

Question

The two ends of a metal rod are matainted at temperatures 100oC and 110oC. The rate of heat flow in the rod is found to be 4.0 J/s. If the ends are maintained at temperatures 200oC and 210oC, the rate of heat flow will be :

Options

A.16.8 J/s
B.8.0  J/s
C.4.0  J/s
D.44.0  J/s

Solution

Rate of heat flow ∝ temperature difference between two ends
 ⇒ ∝ (T2 − T1)
Here temperature differnece in both case is same (i.e. 10oC)
So, rate of heat flow will also be same
So, = 4J/s

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