NEET | 2016Geometrical OpticsEasy

Question

The angle of incidence for a ray of light at a refracting surface of a prism is 45o. The angle of prism is 60o. Ifthe ray suffers minimum deviation through the prism, the angle of minimum deviation and refractive index ofthe material of the prism respectively, are:

Options

A.

45o ; 12

B.

30o ; 2

C.

45o ; 2

D.

30o ; 12

Solution

At minimum deviation δmin = 2i - A
δmin = 2(45) - 60
δmin = 30o
Refractive index of material is
μ=sinδmin+A2sin A2=sin30+602sin(30o)
μ=sin 45osin 30o=1212=2

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