AIPMT | 2015SHMHard
Question
A particle is executing SHM along a straight line. Its velocities at distances x1 and x2 from the mean position are V1 and V2, respectively. Its time period is :-
Options
A.
B.
C.
D.
Solution
For particle undergoing SHM
V = ω
So V1 = ω
& V2 = ω
solving these two equations we get
ω =
⇒ T = 2π
Hence option (1)
V = ω
So V1 = ω
& V2 = ωsolving these two equations we get
ω =
⇒ T = 2π
Hence option (1)
Create a free account to view solution
View Solution FreeMore SHM Questions
The phase of a particle in S.H.M at time t is . The following inference is drawn from this...A cylindrical block of mass M and area of cross section A is floating in a liquid of density $\rho$ and with its axis ve...What would be the period of the free oscillations of the system shown here if mass M1 is pulled down a little force cons...In the given diagram S1 and S2 are indentical springs. The frequency of oscillation of the mass M is f. If one of the sp...A block of mass m is resting on a piston as shown in figure which is moving vertically with a SHM of period 1 s. The min...