AIPMT | 2015SHMHard
Question
A particle is executing SHM along a straight line. Its velocities at distances x1 and x2 from the mean position are V1 and V2, respectively. Its time period is :-
Options
A.
B.
C.
D.
Solution
For particle undergoing SHM
V = ω
So V1 = ω
& V2 = ω
solving these two equations we get
ω =
⇒ T = 2π
Hence option (1)
V = ω
So V1 = ω
& V2 = ωsolving these two equations we get
ω =
⇒ T = 2π
Hence option (1)
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