AIPMT | 2015SHMHard
Question
A particle is executing SHM along a straight line. Its velocities at distances x1 and x2 from the mean position are V1 and V2, respectively. Its time period is :-
Options
A.
B.
C.
D.
Solution
For particle undergoing SHM
V = ω
So V1 = ω
& V2 = ω
solving these two equations we get
ω =
⇒ T = 2π
Hence option (1)
V = ω
So V1 = ω
& V2 = ωsolving these two equations we get
ω =
⇒ T = 2π
Hence option (1)
Create a free account to view solution
View Solution FreeMore SHM Questions
Which of the following functions represent SHM?...Two particles execute S.H.M. of same amplitude and frequency along the same straight line from same mean position. They ...The maximum K.E. of a oscillating spring is 5 joules and its amplitude 10 cms. The force constant of the spring is :...A mass of 1 kg attached to the bottom of a spring has a certain frequency of vibration. The following mass has to be add...A particle is dropped from a height equal to the radius of the earth above the tunnel dug through the earth as shown in ...