JEE Advanced | 2013Solid StateHard
Question
The arrangement of X- ions around A+ ion in solid AX is given in the figure (not drawn to scale).If the radius of X- is 250 pm, the radius of A+ is -
Options
A.104 pm
B.125 pm
C.183 pm
D.57 pm
Solution
Limiting radius ratio for octahedral void is 
r+ = 0.414 × 250 pm ≃ 104 pm
Correct option (A)
r+ = 0.414 × 250 pm ≃ 104 pm
Correct option (A)
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