Redox and Equivalent ConceptHard
Question
Expermentally it was found that a metal oxide has formula M0.98O. Metal M, is present as M2+and M3+ in its oxide. Fraction of the metal which exists as M3+ would be :-
Options
A.7.01%
B.4.08%
C.6.05%
D.5.08%
Solution
Let no. of oxygen atom = 100
∴ no. of metal atom = 98
if no. of M+2 ion = x
then no. of M+3 ion = (98 - x)
Since compound is electrically neutral
x × (12) + (98 - x)x + 3 + 100 × (-2) = 0
2x + 98 × 3 - 3x - 200 = 0
294 - 200 - x = 0
x = 94
∴ No. of M+2 ion = 94
No. of M+3 ion = 98 - 94 = 4
∴ Fraction of metal which exists as M+3would be
∴ no. of metal atom = 98
if no. of M+2 ion = x
then no. of M+3 ion = (98 - x)
Since compound is electrically neutral
x × (12) + (98 - x)x + 3 + 100 × (-2) = 0
2x + 98 × 3 - 3x - 200 = 0
294 - 200 - x = 0
x = 94
∴ No. of M+2 ion = 94
No. of M+3 ion = 98 - 94 = 4
∴ Fraction of metal which exists as M+3would be
Create a free account to view solution
View Solution FreeMore Redox and Equivalent Concept Questions
The number of electrons lost per mole of ethanol in its oxidation into acetic acid is...In the following redox reactions, NH3 appears either in reactant or product. In which case, the equivalent weight of NH3...Consider the following reactions:In the product ' C ', ' X ' is the number of units, ' Y ' is the total number oxygen at...A small amount of CaCO3 completely neutralizes 525 ml of 0.1 N-HCl and no acid is left at the end. After converting all ...At 298 K, the standard reduction potentials are 1.51 V for MnO4- |Mn2+, 1.36 V for Cl2|Cl- , 1.07 V for Br2|Br, and 0.54...