Differential EquationHard
Question
Two capacitors C1 and C2 are charged to 120V and 200V respectively. It is found that by connecting them together the potential on each one can be made zero. Then :
Options
A.5C1 = 3C2
B.3C1 = 5C2
C.3C1 + 5C2 = 0
D.9C1 + 4C2
Solution
Common voltage 
(+ ive plate of one capacitor is connected with - ive plate of second capacitor)
⇒ 120 C1 = 200 C2 ⇒ 3C1 = 5C2.
(+ ive plate of one capacitor is connected with - ive plate of second capacitor)
⇒ 120 C1 = 200 C2 ⇒ 3C1 = 5C2.
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