Differential EquationHard

Question

If y(x) satisfies the differential equation y′ - ytanx = 2x secx and y(0) = 0, then

Options

A.
B.
C.
D.

Solution

- y tan x = 2x sec x
cos x + (- sin x) y = 2x
(y cos x) = 2x
y (x) cos x = x2 + c, where c = 0 since y (0) = 0
when x = , when x =
when x =
when x =

Create a free account to view solution

View Solution Free
Topic: Differential Equation·Practice all Differential Equation questions

More Differential Equation Questions

Let the solution curve of the differential equation $xdy - ydx = \sqrt{x^{2} + y^{2}}dx,x > 0,y(1) = 0$, be $y = y(x)...The solution of the differential equation, = x2 is-...The solution of the differential equation x = y (log y − log x + 1) is-...The solution of the equation + y tan x = xm cos x is-...The solution of the differential equation (1 + cos x) dy = (1 − cos x) dx is-...