Indefinite IntegrationHard
Question
If I = 
ex sin 2x dx, then for what value of k, kI = ex (sin 2x − 2 cos 2x) + constant-
ex sin 2x dx, then for what value of k, kI = ex (sin 2x − 2 cos 2x) + constant-Options
A.1
B.3
C.5
D.7
ex sin 2x dx, then for what value of k, kI = ex (sin 2x − 2 cos 2x) + constant-