Straight LineHard
Question
Let P = (-1,0),Q = (0, 0) and R = (3, 3√3) br three points. Then, the equations of the bisector of the angle PQR is
Options
A.
B.x + √3y = 0
C.√3x + y = 0
D.
Solution
The line segment OR makes an angle of 60o with the positive direction of x-axis.
So, the bisector of the angle PQR will make an angle of 60o with the negative direction of axis it will therefore have angle of inclination of 120o and o its equation is
y - 0 = tan120o(x - 0)
⇒ y = - √3x
⇒ y + √3 = 0
So, the bisector of the angle PQR will make an angle of 60o with the negative direction of axis it will therefore have angle of inclination of 120o and o its equation is
y - 0 = tan120o(x - 0)
⇒ y = - √3x
⇒ y + √3 = 0
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