Laws of MotionHard
Question
In order to raise a mass m a man ties it to a rope and passes the rope over a frictionless pulley. He climbs the rope with an acceleration 3g/2 relative to the rope. If the mass of the man is m/2 and the mass of the rope is negligible, the tension in the rope is :-
Options
A.
B.
C.
D.
Solution
Let T be the tension in the rope and a its acceleration. Therefore, the acceleration of the man = 
The equations of motion of the mass and the man are
T - mg = ma ...(i)
and T -
...(ii)
Eliminating a from Eqs. (i) and (ii). we get
T =
The equations of motion of the mass and the man are
T - mg = ma ...(i)
and T -
...(ii)Eliminating a from Eqs. (i) and (ii). we get
T =
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