Laws of MotionHard
Question
In order to raise a mass m a man ties it to a rope and passes the rope over a frictionless pulley. He climbs the rope with an acceleration 3g/2 relative to the rope. If the mass of the man is m/2 and the mass of the rope is negligible, the tension in the rope is :-
Options
A.
B.
C.
D.
Solution
Let T be the tension in the rope and a its acceleration. Therefore, the acceleration of the man = 
The equations of motion of the mass and the man are
T - mg = ma ...(i)
and T -
...(ii)
Eliminating a from Eqs. (i) and (ii). we get
T =
The equations of motion of the mass and the man are
T - mg = ma ...(i)
and T -
...(ii)Eliminating a from Eqs. (i) and (ii). we get
T =
Create a free account to view solution
View Solution FreeMore Laws of Motion Questions
Let E,G and N represents the magnitude of electromagnetic, gravitational and nuclear forces between two protons at a giv...Two masses m1 and m2 (m1 2) are released from rest from a finite distance. They start under their mutual gravitational a...Block A of mass 35 kg is resting on a frictionless floor. Another block B of mass 7 kg is resting on it as shown in the ...A boy of mass 50 kg is standing in a lift moving down with an acceleration 9.8 m/s2. the apparent weight of the boy is (...An object of mass 150 kg. is to be lowered with the help of a string whose breaking strength is 100 kg.-wt. What should ...