Continuity and DifferentiabilityHard
Question
Let h(x) = min {x, x2} for every real number of x, then
Options
A.h is differentiable for all x
B.h is continuous for all x
C.h′(x) = 1, for all x > 1
D.h is not differentiable at two values of x,
Solution
From the figure.
h(x) is continuous all x, but h(x) is not differentiable at two points x = 0 and x = 1 (due to sharp edges). Also h′(x) = 1, ∀ x > 1
Hence (b),(c) and (d) is correct answers.
Create a free account to view solution
View Solution FreeMore Continuity and Differentiability Questions
If x = a cos, y = b sin, then is equal to -...State which of the following is a false statement-...If x = cosecθ - sinθ ; y = cosecnθ - sinnθ, then (x2 + 4) - n2y2 equals to...Suppose that f is a differentiable function with the property that f(x + y) = f(x) + f(y) + xy and f(h)/h = 3 then -...If y = tan−1, then value of dy/dx is-...