Continuity and DifferentiabilityMedium
Question
Let f : R → R be such that f(1) = 3 and f′(1) = 6 Then,
equals
equalsOptions
A.1
B.e1/2
C.e2
D.e3
Solution
Let y 
⇒ log y =
[log f(1 + x) - log f (1)]
log y =
( using L′ Hospital′s rule)
⇒ log
= 2
⇒

⇒ log y =
[log f(1 + x) - log f (1)]
log y =
( using L′ Hospital′s rule)
⇒ log
= 2⇒
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