Continuity and DifferentiabilityHard
Question
Which of the following function is differentiable at x = 0 ?
Options
A.cos (|x|) + |x|
B.cos (| x |) - | x |
C.sin (| x |) + | x |
D.sin (| x |) - | x |
Solution
RHD of sin (| x |) - | x | 
= 1 - 1 = 0 (∵ f(0) = 0)
RHD of sin (| x |) - | x |
Therefore, (d) is the answer.
= 1 - 1 = 0 (∵ f(0) = 0)RHD of sin (| x |) - | x |
Therefore, (d) is the answer.
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