FunctionHard
Question
The domain of definition of f (x) = 
is
isOptions
A.R / {-1,-2}
B.(-2, ∞)
C.R /{-1,-2,-3}
D.(-3, ∞) / {-1,-2}
Solution
Given f(x) 
For numberator x + 3 > 0 ⇒ x > -3 .....(i)
and for denominator (x +1)(x + 2) ≠ 0
⇒ x ≠ - 1, -2 .....(ii)
From Eqs. (i) and (ii),
Domain is (-3, ∞)/{-1, -2}
For numberator x + 3 > 0 ⇒ x > -3 .....(i)
and for denominator (x +1)(x + 2) ≠ 0
⇒ x ≠ - 1, -2 .....(ii)
From Eqs. (i) and (ii),
Domain is (-3, ∞)/{-1, -2}
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