Binomial TheoremHard

Question

If in the expansion of (1+ x)m (1 - x)n, the coefficients of x and x2 are 3 and - 6respectively, then m is

Options

A.6
B.9
C.12
D.24

Solution

(1 + x)m (1 - x)n =
= 1 + (m - n)x + x2 + ....
term containing power of x ≥ 3.
Now,     m - n = 3       ....(i)
      (∵ coefficient of x = 3 given)
and     m(m - 1) + n(n - 1) - mn = - 6
⇒       m(m -1) + n(n -1) - 2mn = - 12
⇒       m2 - m + n2 - n - 2mn = - 12
⇒       (m - n)2 - (m + n) = - 12
⇒       m+ n = 9 + 12 = 21       ......(ii)
On solving Eqs. (i) and (ii) , we get
          m = 12

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