Permutation and CombinationHard
Question
How many dofferent nine digit numbers can be formed form the number 22 33 55 888 by rearranging its digis so that the odd digits occupy even positions
Options
A.16
B.63
C.60
D.180
Solution
X - X - X - X - X. The four digits 3, 3, 5, 5, czn be arraged at (-) places in 
= 6 ways.
The five digits 2,2, 8, 8, 8, can be arranged at (X) places in
ways = 10 ways.
Total number of arrangements = 6 × 10 = 60 ways
(Since, event A and B are independent, therefore A
B = A × B).
= 6 ways.The five digits 2,2, 8, 8, 8, can be arranged at (X) places in
ways = 10 ways. Total number of arrangements = 6 × 10 = 60 ways
(Since, event A and B are independent, therefore A
B = A × B).Create a free account to view solution
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