Quadratic EquationHard
Question
Let α, β be the roots of the equation (x - a)(x - b) = c, c ≠ 0
Then the roots of the equation (x - α)(x - β) + c = 0
Then the roots of the equation (x - α)(x - β) + c = 0
Options
A.a, c
B.b, c
C.a, b
D.a + c, b + c
Solution
Given α, β are the roots of (x - a)(x - b) - c = 0
⇒ (x - a)(x - b)- c = (x - α) (x - β)
⇒ (x - a)(x - b) = (x - α)(x - β) + c
⇒ a, b are the roots of equation (x - α)(x - β) + c = 0
⇒ (x - a)(x - b)- c = (x - α) (x - β)
⇒ (x - a)(x - b) = (x - α)(x - β) + c
⇒ a, b are the roots of equation (x - α)(x - β) + c = 0
Create a free account to view solution
View Solution FreeMore Quadratic Equation Questions
If log0.3 (x - 1) 0.09 (x - 1), then x lies in the interval...If 1 lies between the roots of the quadratic equation 3x2 - 3sinθ.x + 2sin2θ = 2, then range of ′θ&...the product of the roots of the equation x2 − 2√2 kx + 2 e2 log k − 1 = 0 is 31, then the roots of the...The number of values of k, for which the system of equations :(k + 1)x + 8y = 4kkx + (k + 3)y = 3k - 1has no solution, i...Let α and β be the distinct roots of ax2 + bx + c = 0, then isequal to...