Momentum and CollisionEasy
Question
A bullet of mass m travelling at speed v strikes a block of mass M at rest and gets embedded in it. Finally both will have combined kinetic energy :-
Options
A.
B.
C.
D.
Solution
By COLM
mv + 0 = (m + M)v′
then v′ =
KE =
(m M)v′2
=
(m M) 
=
mv2 
mv + 0 = (m + M)v′
then v′ =
KE =
(m M)v′2=
(m M) =
mv2 Create a free account to view solution
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