Redox and Equivalent ConceptEasy
Question
The standard reduction potential for Cu+ / Cu is + 0.34 volt. Calculate the reduction potential at pH = 14 for half cell Cu+2/Cu. Ksp of Cu(OH)2 is 1.0 × 10-19 :-
Options
A.- 0.442 volt
B.- 0.221 volt
C.+0.442 volt
D.None of these
Solution
Ksp = [Cu+2][OH-]2
∴ PH = 14 ⇒ POH = 0
∴ (OH-) = 1 M
∴ 1.0 × 10-19 = [Cu+2] [1]2
[Cu+2] = 10-19 M
Ered = Eored +
log [Cu+2]
= 0.34 +
log 10-19
= - 0.221 volt
∴ PH = 14 ⇒ POH = 0
∴ (OH-) = 1 M
∴ 1.0 × 10-19 = [Cu+2] [1]2
[Cu+2] = 10-19 M
Ered = Eored +
log [Cu+2]= 0.34 +
log 10-19= - 0.221 volt
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