Binomial TheoremHard

Question

The value of (2nCn − nC1. 2n−2Cn + nC2. 2n−4Cn ...) is equal to-

Options

A.0
B.n. 2n
C.2n
D.None of these

Solution

-

Create a free account to view solution

View Solution Free
Topic: Binomial Theorem·Practice all Binomial Theorem questions

More Binomial Theorem Questions

If the 4th term in the expansion of is , then the values of a and n are-...If (15Cr + 15Cr-1) (15C15-r + 15C16-r) = (16C13)2, then the value of r is -...The coefficient of x5 in the expansion of (1 + x)3.(1 − x)6 is -...If ′a′ be the sum of the odd terms & ′b′ be the sum of the even terms in the expansion of (1 + x...If (1 + x)n = C0 + C1x + C2x2 +....+ Cnxn , then C0 − + ....+ (−1)n is equal to -...