Area under the curveHard
Question
The area bounded by circle x2 + y2 = 4 ;
curve y =
(where [ . ] is G.I.F.) and the x-axis ; is
curve y =
(where [ . ] is G.I.F.) and the x-axis ; isOptions
A.π/3 + √3 square unit
B.2π/3 + √3 square unit
C.π/4 + √3 square unit
D.π/2 + √3 square unit
Solution
For x ∈ [- 2, 2] ; - 
cos
≥ cos2 
i.e.
Also,
∴
∴ y = 1
Required Area = 2(Area of sector) + Area of ᐃ
= 2
× 2√3 × 1
= 4
+ √3
=
square unit.
cos
≥ cos2 i.e.
Also,
∴
∴ y = 1
Required Area = 2(Area of sector) + Area of ᐃ
= 2
× 2√3 × 1 = 4
+ √3=
square unit.Create a free account to view solution
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