Area under the curveMedium
Question
Area bounded by the curves y =
and √y = |x - 1| is -
and √y = |x - 1| is -Options
A.2
(
- (x - 1)2)dx
(
- (x - 1)2)dxB.2
(√x - x2) dx
(√x - x2) dxC.2
(
- (2-x)2)dx
(
- (2-x)2)dxD.

Solution

y =
and √y = |x - 1|both curves intersect at (0, 1), (1, 0) and (2, 1)
required area = 2
(y2 - y1) dx ⇒ ⇒ A = 2
[
- (x - 1)2]dx ...... (1)= 2

Apply
f(x)dx =
f(a + b - x)dx in (1)⇒ A = 2
[
-(2 - x)2]dxRequired area can also be calculated as
2
(y4 - y3)dx= 2
[
- (x - 1)2]dx
Apply
f(x)x =
f(a + b - x)dx⇒ A = 2
[√x - x2]dxCreate a free account to view solution
View Solution FreeMore Area under the curve Questions
The area between the curve y = ex and x-axis which lies between x = − 1 and x = 1 is-...The area bounded by the curves y = e|x|, y = e–|x| and |x| = 1, is-...The area enclosed between the curves y = loge(x + e) x = loge and the x-axis is equal to...The area bounded by the curves y = x(1 - lnx) and positive x-axis between x = e-1 and x = e is -...Suppose y = f(x) and y = g(x) are two functions whose graphs intersect at three points (0, 4), (2, 2) and (4, 0) with f(...