CircleHard
Question
If y = 3x is a tangent to a circle with centre (1, 1), then the other tangent drawn through (0, 0) to the circle is :-
Options
A.3y = x
B.y = -3x
C.y = 2x
D.y = -2x
Solution
Radius of the circle = Perpendicular distance of (1, 1) from y - 3x = 0
=
Let the other tangent be y - kx = 0
⇒ Perpendicular distance from (1, 1) = radius
⇒
⇒ k = 3, 
Therefore other tangent is y =
x
=
Let the other tangent be y - kx = 0
⇒ Perpendicular distance from (1, 1) = radius
⇒
Therefore other tangent is y =
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