Alternating CurrentHard
Question
A coil of inductance 8.4 mH and resistance 6Ω is connected to 12 V battery. The current in the coil is 1 A at approximately the time
Options
A.500 s
B.20 s
C.35 ms
D.1 ms
Solution
The current-time (i-t) equation in L-R circuit is given by
[Growth of current in L-R circuit]
i = i0(1-e-t/tL) ........(i)
where
and
and
and i = 1A
t = ?
Substituting these values in Eq. (i), we get
t = 0.97 × 10-3s
or t = 0.97 ms
t
1 ms
[Growth of current in L-R circuit]
i = i0(1-e-t/tL) ........(i)
where
and
and
and i = 1A
t = ?
Substituting these values in Eq. (i), we get
t = 0.97 × 10-3s
or t = 0.97 ms
t
1 msCreate a free account to view solution
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