Alternating CurrentEasy
Question
The current I = I0 sin(ωt − π/2) is flowing in a variable current circuit. The potential E = E0 sinωt is applied to the circuit. The loss of power will be :
Options
A.P = E0 I0 /
B.P = E0 I0 /2
C.P = EI /
D.P = zero
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