AIPMT | 2014ElectrostaticsHard
Question
In a region, the potential is represented by V(x, y, z) = 6x - 8xy - 8y + 6yz, where V is in volts and x, y, z are in metres. The electric force experienced by a charge of 2 coulomb situated at point (1, 1, 1) is
Options
A.6√5 N
B.30 N
C.24 N
D.
Solution
V = 6x - 8xy - 8y + 6yz
Ex = -
= -(6 - 8y) = 2
Ey = -
= -(-8x - 8 + 6z) = 10
Ez = -
= - 6y = - 6
E =
= 2
F = qE = 4
Ex = -
= -(6 - 8y) = 2Ey = -
= -(-8x - 8 + 6z) = 10Ez = -
= - 6y = - 6E =
= 2
F = qE = 4
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