ElectrostaticsHard
Question
An imaginary closed surface P is constructed around a neutral conducting wire connected to a battery and a switch as shown in figure. As the switch is closed, the free electrons in the wire start moving along the wire. In any time interval, the number of electrons entering the closed surface P is equal to the number of electrons leaving it. On closing the switch, the flux of the electric field through the closed surface:
Options
A.remains unchanged
B.remains zero
C.is increased
D.is decreased
Solution
Since, no. of electrons entering = no of electrons leaving.
⇒ Net enclosed charge is constant
⇒ Flux is constant
⇒ Net enclosed charge is constant
⇒ Flux is constant
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