Photoelectric EffectEasy

Question

The work functions of metals A and B are in the ratio 1 : 2. If light of frequencies ƒ and 2ƒ are incident on the surface of A and B respectively, the ratio of the maximum kinetic energies of photoelectrons emitted is (ƒ is greater than threshold frequency of A, 2ƒ is greater than threshold frequency of B)

Options

A.1 : 1
B.1 : 2
C.1 : 3
D.1 : 4

Solution

KA = hf - φ               .....(1)
KB = 2hf - 2φ                .....(2)
⇒    1 : 2

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