Photoelectric EffectHard
Question
The energy of the reaction Li1 + p 
2 He4 is (the binding energy per nucleon in Li7 and He4 nuclei are 5.60 and 7.06 MeV respectively.)
2 He4 is (the binding energy per nucleon in Li7 and He4 nuclei are 5.60 and 7.06 MeV respectively.) Options
A.17.3 MeV
B.1.73 MeV
C.1.46 MeV
D.depends on binding energy of proton
Solution
Q = (2BEHe − BELi)
= (2 × 7.06 × 4 − 5.60 × 7) Mev
= 17.28 Mev.
= (2 × 7.06 × 4 − 5.60 × 7) Mev
= 17.28 Mev.
Create a free account to view solution
View Solution FreeMore Photoelectric Effect Questions
A proton is accelerated through potential difference of 1 V then KE of proton will be :...Proton and α - particles have the same De-broglie wavelength. What can be same for both of them :...The energy difference between the first two levels of hydrogen atom is 10.2 eV. What is the corresponding energy differe...Light of wave length 4000 is incident on a sodium surface for which the threshold wave length of photoelectrons is 5420....Which of the following is related with characteristic emission of X-ray :...