Geometrical OpticsHard
Question
A point source of light S, placed at a distance L in front of the centre of a plane mirror of width d, hangs vertically on a wall. A man walks in front of the mirror along a line parallel to the mirror at a distance 2L from it as shown. The greatest distance over which he can see the image of the light source in the mirror is
Options
A.d / 2
B.d
C.2 d
D.3 d
Solution
The ray diagram will be as follows :
HI = AB = d
DS = CD =
Since, AH = 2 AD
∴ GH = 2 CD = 2
Similarly, IJ = d
∴ GJ = GH + HI + IJ
= d + d + d = 3 d.
Create a free account to view solution
View Solution FreeMore Geometrical Optics Questions
An object is situated at a distance of 15 cm from a convex mirror of focal length 30 cm. The position of the image forme...The incorrect statement with regard to Haemophilia is :...A ray of light propagates from glass (refractive index = 3/2) to water ( refractive index = 4/3). The value of the criti...Two thin lenses, one of focal length + 60 cm and the other of focal length -20 cm are put in contact. The combined focal...A person wears glasses of power - 2.5 D. The defect of the eye and the far point of the person without the glasses are r...