Geometrical OpticsEasy
Question
A point source of light S, placed at a distance L in front of the centre of a plane mirror of width d, hangs vertically on a wall. A man walks in front of the mirror along a line parallel to the mirror at a distance 2L from it as shown. The greatest distance over which he can see the image of the light source in the mirror is
Options
A.d / 2
B.d
C.2 d
D.3 d
Solution
The ray diagram will be as follows :
HI = AB = d
DS = CD =
Since, AH = 2 AD
∴ GH = 2 CD = 2
Similarly, IJ = d
∴ GJ = GH + HI + IJ
= d + d + d = 3 d.
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