Geometrical OpticsHard
Question
The diagram shows five isosceles right angle prisms. A light ray incident at 90o at the first face emerges at same angle with the normal from the last face. Which of the following relations hold regarding the refractive indices ?


Options
A.μ12 + μ32 + μ52 = μ22 + μ42
B.μ12 + μ32 + μ52 = 1 + μ22 + μ42
C.μ12 + μ32 + μ52 = 2 + μ22 + μ42
D.None of these
Solution

1 sin 90o = μ1 sin r1 ; μ2 sin r2 = μ1 cos r1
μ2 cos r2 = μ3 sin r3
μ4 sin r4 = μ3 cos r3 ; μ4 cos r4 = μ5 sin r5
1.90o = μ5 cos r5
Square and add 1 + μ22 + μ42 = μ12 + μ32 + μ52
Create a free account to view solution
View Solution FreeMore Geometrical Optics Questions
A thin glass (refractive index 1.5) lens has optical power of - 5D in air. Its optical power in a liquid medium with ref...The magnifying power of telescope is found to be 9 and seperation between lenses is 20cm. what are focal lengths of comp...A ray is incident at 30o angle on plane mirror. What will be deviation after reflection from mirror....A transparent solid cylindrical rod has a refractive index of . It is surrounded by air. A light rayis incident at the m...An eye specialist prescribes spectacles having combination of convex lens of focal length 0 cm in contact with a concave...