Math miscellaneousHard
Question
Let 
= Ax4 + Bx3 + Cx2 + Dx + E then the value of 5A + 4B + 3C + 2D + E is equal to
= Ax4 + Bx3 + Cx2 + Dx + E then the value of 5A + 4B + 3C + 2D + E is equal toOptions
A.-17
B.-14
C.-11
D.-8
Solution
Multiplying both sides by x then
= Ax5 + Bx4 + Cx3 + Dx2 + Ex
Differentiating both sides w.r.t. x and the putting x = 1
= 5A + 4B + 3C + 2D + E = - 11.
= Ax5 + Bx4 + Cx3 + Dx2 + Ex Differentiating both sides w.r.t. x and the putting x = 1
= 5A + 4B + 3C + 2D + E = - 11.
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