Math miscellaneousHard
Question
If I1 = 
2x2 dx, I2, = 2x3 dx, I3
2x2dx and I4 = 223 dx then
2x2 dx, I2, = 2x3 dx, I32x2dx and I4 = 223 dx thenOptions
A.I2 > I1
B.I1 > I2
C.I3 = I4
D.I3 > I4
Solution
I1 = 
2x2 dx, I2 = 2x3 dx, I3 = 2x2 dx I4 = 2x3 dx
∀ 0 < x < 1, x2 > x3
⇒2x2 dx > 2x3 dx
⇒ I1 > I2.
2x2 dx, I2 = 2x3 dx, I3 = 2x2 dx I4 = 2x3 dx ∀ 0 < x < 1, x2 > x3
⇒
2x2 dx > 2x3 dx⇒ I1 > I2.
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