Ionic EquilibriumEasy
Question
or the equibrium CH3COOH(eq.) + H2O(l) ⇋ CH3COO-(aq.) + H3O+ (aq) ?
Ka = 1.70 × 10-4 at 298 K. What is the effect on the pH of adding 50 ml of 0.01 M CH3COONa to the solution.
Ka = 1.70 × 10-4 at 298 K. What is the effect on the pH of adding 50 ml of 0.01 M CH3COONa to the solution.
Options
A.pH value decreases.
B.pH value increases.
C.pH will unchanged.
D.Can not find out.
Solution
CH3COOH + H2O ⇋ CH3COO- + H3O+
CH3COONa → CH3COO- + Na+
backward reaction H+ ↓ pH ↑
CH3COONa → CH3COO- + Na+
backward reaction H+ ↓ pH ↑
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